1.

if a bus travelling at 20m /s is subjected to steady deceleration of 5m/s square how long will it take to come to rest ​

Answer»

Answer:

Initial velocity with which the bus is moving = u= 20m/s.

Final velocity which it has to GAIN = v= 0m/s.

Deceleration = 5 m/s^2.

Applying,

v = u - at

=> 0 = 20 - 5 ×t

=> 5t = 20

=> t= 4s.

Hence, TIME taken = 4 SECONDS



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