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if a bus travelling at 20m /s is subjected to steady deceleration of 5m/s square how long will it take to come to rest |
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Answer» Answer: Initial velocity with which the bus is moving = u= 20m/s. Final velocity which it has to GAIN = v= 0m/s. Deceleration = 5 m/s^2. Applying, v = u - at => 0 = 20 - 5 ×t => 5t = 20 => t= 4s. |
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