1.

If a car at rest accelerates uniformly to a speed of 144km/h in 20s, it covers a distance:

Answer»

speed = 144km/h
          = 144*5/18 = 40m/s
apply
V = u + at
v = 40m/s
u = 0m/s
a = ?
t = 20 s
40 = 0 + 20*a
a = 2m/s²
apply
s = UT  + at²/2
s = ?
u = 0m/s
a = 2m/s²
t = 20s
s = 0 + 2*20²/2
s = 400m
hence CAR covers 400 meter.



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