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If a charged spherical conductor of radius `10 cm` has potential `V` at a point distant `5 cm` from its centre, then the potential at a point distant `15 cm` from the centre will beA. `(1)/(3) V`B. `(2)/(3) V`C. `(3)/(2) V`D. `3 V` |
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Answer» Correct Answer - B Potential inside the sphere will be same as that on its surface i.e, `V = V_(surface) = (q)/(10)` stat volt `V_(out) = (q)/(15)` stat volt `:. (V_(out))/(V) = (2)/(3) rArr V_(out) = (2)/(3)V` |
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