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If a charged spherical conductor of radius 10cm haspotential V at a point distant 5 cm from its centre, then thepotential at a point distant 15 cm from the centre will be |
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Answer» Potential at any point inside the conductor will be same as surfaceSo V =K /rWhere k is constant and r is the distance from centreSo V =k/ 10K =10VVat r=15=k/15=10V/15=2/3V |
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