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If a projectile is fired at an angle `theta` with the vertical with velocity u, then maximum height attained is given by:-A. `(u^(2)cos theta)/(2g)`B. `(u^(2)sin^(2)theta)/(2g)`C. `(u^(2)sin^(@)theta)/(g)`D. `(u^(2)cos^(2)theta)/(2g)` |
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Answer» Correct Answer - D `H=(u_(y)^(2))/(2g)=(u^(2)cos^(2)theta)/(2g)` |
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