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If a rubber ball is taken at the depth of 200 m in a pool its volume decreases by 0.1%. If the density ofthe water is 1 x 10° kg/m and g 10 m/s, then the volume elasticity in N/m2 will be :(A) 10(B) 2 x 108(C) 10(D) 2 x 109 |
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Answer» ρ = 1 × 103kg/m3h = 200mg = 10 m/s2(ΔV / V) = 0.1%volume elasticity= K = {ΔP / (ΔV / V)}= {hρg / (ΔV / V)}= {(200 × 1 × 103× 10) / (0.1 / 100)}= 2 × 109N/m2 |
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