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If a simple harmonic motion is erpresented by `(d^(2)x)/(dt^(2))+ax=0`, its time period is.A. `(2pi)/(k)`B. `2pi k`C. `(2pi)/(sqrt(k)`D. `2pi sqrt(k)` |
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Answer» Correct Answer - C On comparing with standered equation `(d^(2)y)/(dt^(2) + omega^(2) y = 0` we get `omega^(2) = k rArr omega = (2pi)/(T) = sqrt(k) rArr = (2pi)/(sqrt(k)` |
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