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If `A = sin^2 theta+ cos^4 theta`, then for all real values of `theta`A. `1leAle2`B. `(3)/(4) le A le 1`C. `(13)/(16) le A le 1`D. `(3)/(4) le A le (13)/(16)` |
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Answer» Correct Answer - B Given, `A - sin^(2) theta+(1-sin^(2) theta)^(2)` `implies A = sin^(4) theta - sin^(2) theta + 1` `implies A = (sin^(2)theta-(1)/(2))^(2)+(3)/(4)` `implies 0le (sin^(2)theta-(1)/(2))^(2)le(1)/(4) " "[because 0 le sin^(2) theta le 1]` `therefore (3)/(4) le A le 1` |
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