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If A + B + C = `180^(@)`, then prove that tan A + tan B + tan C = tan A tan B tan C. |
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Answer» Since, A + B = `180^(@)C` `therefore tan(A + B) = tan(180^(@)-C)` `implies (tanA+tanB)/(1-tanAtanB)=-tanC` `implies tanA + tanB =- tan C + tan A tan B tan C` `implies tanA + tanB +tanC = tanA tanB tanC` |
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