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If a spherical ball rolls on a table without slipping, the fraction of its total energy associated with rotation isA. `3/5`B. `2/7`C. `3/5`D. `3/7` |
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Answer» Correct Answer - B `f_(r)=(1/2Iomega^(2))/(1/2mv^(2)+1/2Iomega^(2)), where I=2/5mr^(2)` `omega=v/r` solve to get `f_(r)=2/7` |
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