If `alpha=3sin^-1(6/11) `and `beta=3cos^-1(4/9)`, where the inverse trigonometric functions take only the principal values, then the correct option(s) is (are)A. `cos beta gt 0`B. `sin beta lt 0`C. `cos (alpha + beta) gt 0`D. `cos alpha lt 0`

If `alpha=3sin^-1(6/11) `and `beta=3cos^-1(4/9)`, where the inverse tr

1.	If `alpha=3sin^-1(6/11) `and `beta=3cos^-1(4/9)`, where the inverse trigonometric functions take only the principal values, then the correct option(s) is (are)A. `cos beta gt 0`B. `sin beta lt 0`C. `cos (alpha + beta) gt 0`D. `cos alpha lt 0`
Answer» Correct Answer - B::C::D `alpha = 3 sin^(-1).(6)/(11) gt 3 sin^(-1).(6)/(12) = 3 sin^(-1).(1)/(2) = (pi)/(2)` and `beta = 3 cos^(-1).(4)/(9) gt 3 cos^(-1).(4)/(8) = pi` So, `alpha gt (pi)/(2) and beta gt pi` `:. alpha + beta gt (3pi)/(2)`

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