InterviewSolution
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InterviewSolution
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If `alpha and beta` are the roots of `x^2-2 x +4=0` then the value of `alpha^6+beta^6` is |
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Answer» `alpha*beta=4` `alpha+beta=2` `alpha^2+beta^2=(alpha+beta)^2-2alphabeta` `=4-8=-4` `(a+b)^3=a^3+b^3+3ab(a+b)` `(alpha^2+beta^2)^3=alpha^6+beta^6+3alpha^2beta^2(alpha^2+beta^2)` `-64=alpha^6+beta^6+3*16(-4)` `alpha^6+beta^6=192-64=128` option3 is correct. |
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