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If alpha +beeta are the zeroes of the polynomial p(x)=2x^+5x+r such that alpha square+beeta square+alpha×beeta=21÷4 . Find r |
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Answer» R = 2 EXPLANATION: 2x² + 5X + r We know that α+β=-b/a = -5/2 αβ = c/a = r/2 So now , α²+β²+αβ can be written as (α+β)²- αβ bcoz when we will open the bracket then 2αβ-αβ =αβ as given in eqn. So now , (α+β)²-αβ=21/4 now putting the values, (-5/2)²-r/2=21/4 25/4-r/2=21/4 - r/2= - 4/4 minus cancelled r/2=1 r=2 Hope u understood !! Plz mark as brainliest |
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