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If `alpha,beta,gamma` are the roots of the equation `x^3 + 4x +1=0` then `(alpha+beta)^(-1)+(beta+gamma)^(-1)+(gamma+alpha)^(-1)=` |
Answer» For the given equation `alpha + beta + gamma = 0` `alpha beta + beta gamma + alpha gamma = 4, alpha beta gamma = -1` Now, `(alpha + beta)^(-1)+(beta + gamma)^(-1) + (gamma + alpha)^(-1).=(-gamma)^(-1)+(-alpha)^(-1) +(-beta)^(-1)` `=(alpha beta + beta gamma + alpha gamma)/(alpha beta gamma)` = `-(4)/(-1)` = 4. |
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