If `alpha in (-(pi)/(2), 0)`, then find the value of `tan^(-1) (cot alpha) - cot^(-1) (tan alpha)`

If `alpha in (-(pi)/(2), 0)`, then find the value of `tan^(-1) (cot al

1.	If `alpha in (-(pi)/(2), 0)`, then find the value of `tan^(-1) (cot alpha) - cot^(-1) (tan alpha)`
Answer» Correct Answer - `-pi` `tan^(-1) (cot alpha) - cot^(-1) (tan alpha)` `= tan^(-1) ((1)/(tan alpha)) - ((pi)/(2) - tan^(-1) (tan alpha))` `= -(pi)/(2) + (tan^(-1) ((1)/(tan alpha)) + tan^(-1) (tan alpha))` `= -(pi)/(2) - (pi)/(2) " " ("as " (-pi)/(2) lt alpha lt 0)`

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