InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
If `alpha=tan^(-1)((4x-4x^3)/(1-6x^2+x^2)),beta=2sin^(-1)((2x)/(1+x^2))`and `tanpi/8=k ,`then`alpha+beta=piforx in [(1,1)/k]``alpha+betaforx in (-k , k)``alpha+beta=piforx in [(1,1)/k]``alpha+beta=0forx in [-k , k]`A. `alpha + beta = pi " for " x in [1, (1)/(k))`B. `alpha = beta " for " x in (-k, k)`C. `alpha + beta = - pi " for " x in [1, (1)/(k))`D. `alpha + beta = 0 " for " x in (-k, k)` |
|
Answer» Correct Answer - A::B Put `x = tan theta` `rArr alpha = tan^(-1) (tan 4 theta)` `= 4 theta - pi " for " x in [1, (1)/(k))` `= 4 theta " for " x in (-k, k)` Also, `beta - 2(pi - 2 theta) " for " x in [1, (1)/(k))` `= 4 theta " for " x in (-k, k)` |
|