1.

If an = \(\cfrac{n(n+3)}{n+2}\) , then find a17 = ……………A) \(\cfrac{340}{20}\)B) \(\cfrac{341}{19}\)C) \(\cfrac{340}{19}\)D) \(\cfrac{341}{20}\)

Answer»

Correct option is (C) \(\frac{340}{19}\)

We have \(a_n = \frac{n(n+3)}{n+2}\)

\(\therefore\) \(a_{17}=\frac{17(17+3)}{17+2}\)       (Putting n = 17)

\(=\frac{17\times20}{19}=\frac{340}{19}\)

Correct option is C) \(\cfrac{340}{19}\)



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