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If `Arg((z-1)/(z+1))= pi/2` then the locus of z is `) circle with radius 2 2) circle with radius 1 3) straight line 4) pair of lines |
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Answer» `arg ( z_1/z_2) = theta` `arg z_1 - arg z_2 = theta` `ar((z-1)/(z+1)) = pi/2` `arg(z +1) = theta` `arg(z-1) = pi/2 + theta` in `/_ ZAB` `/_ AZB = 180^@ - /_A - /_B` `= 180^@ - theta - pi/2 + theta` `= pi/2` Answer |
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