InterviewSolution
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InterviewSolution
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If `asin^(-1)x-bcos^(-1)x=c ,`then `asin^(-1)x+bcos^(-1)x`is equal to(a)`0 `(b) `(pia b+c(b-a))/(a+b)`(c)`pi/2`(d)`(pia b+c(a-b))/(a+b)` |
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Answer» `asin^(-1)x-bcos^(-1)x=c-(1)` `b(cos^(-1)x+sin^(-1)x)=pi/2*b-(2)` Adding equation 1 and 2 `sin^(-1)x(a+b)=(bpi)/2+c` `sin^(-1)x=((bpi)/2+c)/(a+b)-(3)` `cosx=pi/2-((bx+2c)/(2(a+b)))` `=(pia-2c)/(2(a+b))` `asin^(-1)x+bcos^(-1)x=(xab+c(a-b))/(a+b)` Option D is correct. |
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