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If at each point of the curve `y=x^3-a x^2+x+1,`the tangent is inclined at an acute angle with the positive directionof the x-axis, then`a >0`(b) `a |
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Answer» Correct Answer - C We have, ` y= x^(3)-ax^(2)+x+1 " "...(i) ` ` rArr (dy)/(dx) =3x^(2)-2ax+1 ` It is given that at each point on the curve (i), the tangent is inclined at an acute angle with the positive direction of x-axis. ` therefore (dy)/(dx) ge 0 " for all "(x,y)` lying on the curve (i). ` rArr 3x^(2)-2ax+1 ge 0 " for all " x` ` rArr 4a^(2)-12 le 0 rArr a^(2)-3 le 0 rArr - sqrt(3) le a le sqrt(3) rArr |a| le sqrt(3) ` |
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