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If `(b^2-4a c)^2(1+4a^2) |
Answer» Correct Answer - 2 `((b^(2) - 4ac)^(2))/(16a^(2)) lt (4)/(1 + 4a^(2))` Now , max `(ax^(2) + bx + c) = -((b^(2) - 4ac)/(4a)` Also, `(-2)/(sqrt(1 + 4 a^(2))) lt - (b^(2) - 4ac)/(4a) lt (2)/(sqrt(1 + 4a^(2)))` So, maximum value is alwasys less then 2 (when a `to` 0) . |
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