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If break down voltage of zener diode is 6 V then value of I2 will be :- |
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Answer» Current through the circuit , i= R+1 30
mA Voltage ACROSS 1 kΩ= R+1 30
.1= R+1 30
=V
(Since zener diode is voltage REGULATOR and regulates v z
across resistance R=1kΩ Also i=6mA (Given) R+1 30
=6 30=6R+6 24=6R⟹R= 6 24
=4 kΩ. |
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