1.

If break down voltage of zener diode is 6 V then value of I2 will be :- ​

Answer»

Current through the circuit , i=

R+1

30

mA

Voltage ACROSS 1 kΩ=

R+1

30

.1=

R+1

30

=V

Z

(Since zener diode is voltage REGULATOR and regulates v

z

across resistance R=1kΩ

Also i=6mA (Given)

R+1

30

=6

30=6R+6

24=6R⟹R=

6

24

=4 kΩ.



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