1.

If co-ordinate of point A, B, C are (6, -1), (1, 3) and (x, 8) respectively, then find the value of x where AB = BC.

Answer»

Co-ordinate of points A,B, C are (6, -1), (1, 3) and (x, 8) respectively.

According to question

AB = BC

√((6 - 1)2 + (-1 - 3)2) = √((1 - x)2 + (3 - 8)2)

Squaring both sides

25 + 16 = (1 – x)2 + 25

(1 – x)2 = 16

(1 – x) = ±4

taking +ve sign = 1 – x = 4

x = 1 – 4 = -3

taking -ve sign 1 – x = -4

x = 1 + 4 = 5

So, x = -3 or 5



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