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If co-ordinate of point A, B, C are (6, -1), (1, 3) and (x, 8) respectively, then find the value of x where AB = BC. |
Answer» Co-ordinate of points A,B, C are (6, -1), (1, 3) and (x, 8) respectively. According to question AB = BC √((6 - 1)2 + (-1 - 3)2) = √((1 - x)2 + (3 - 8)2) Squaring both sides 25 + 16 = (1 – x)2 + 25 (1 – x)2 = 16 (1 – x) = ±4 taking +ve sign = 1 – x = 4 x = 1 – 4 = -3 taking -ve sign 1 – x = -4 x = 1 + 4 = 5 So, x = -3 or 5 |
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