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If `cos(2sin^(-1)x)=1/9,`then find the values of `xdot` |
Answer» `cos(2sin^(-1)x)=1/9` Let ` sin^(-1)x=alpha` `x=sinalpha``cos(2alpha)=1/9` `1-2sin^2alpha=1/9` `1-1/9=2sin^2alpha` `2sin^2alpha=8/9` `sin^2alpha=4/9` `x=sinalpha=pm2/3`. |
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