1.

If `cos(2sin^(-1)x)=1/9,`then find the values of `xdot`

Answer» `cos(2sin^(-1)x)=1/9`
Let ` sin^(-1)x=alpha`
`x=sinalpha``cos(2alpha)=1/9`
`1-2sin^2alpha=1/9`
`1-1/9=2sin^2alpha`
`2sin^2alpha=8/9`
`sin^2alpha=4/9`
`x=sinalpha=pm2/3`.


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