If cosec θ = 2 and cot θ = √3p where ‘θ’ is an acute angle

1.	If cosec θ = 2 and cot θ = √3p where ‘θ’ is an acute angle, then p =A) 2B) 1C) 1/2D) √3
Answer» Correct option is: B) 1 Given that cosec \(\theta\) = 2 and cot \(\theta\) = \(\sqrt {3P}\) = \(cot^2 \theta\) = 3P = \(cosec^2 \theta -1 \) = 3P ( \(\because\) \(cot^2 \theta\) = \(cosec^2 \theta -1 \)) = 4-1 = 3P (\(\because\) cosec \(\theta\) = 2) = 3P = 3 = P = \(\frac 33\) = 1 Correct option is: B) 1

If cosec θ = 2 and cot θ = √3p where ‘θ’ is an acute angle, then p =A) 2B) 1C) 1/2D) √3

Answer»

Correct option is: B) 1

Given that cosec \(\theta\) = 2

and cot \(\theta\) = \(\sqrt {3P}\)

= \(cot^2 \theta\) = 3P

= \(cosec^2 \theta -1 \) = 3P ( \(\because\) \(cot^2 \theta\) = \(cosec^2 \theta -1 \))

= 4-1 = 3P (\(\because\) cosec \(\theta\) = 2)

= 3P = 3

= P = \(\frac 33\) = 1

Correct option is: B) 1