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If cosec2 θ = 625/576, then what is the value of [(sin θ – cos θ)/(sin θ + cos θ)]?1). 12). 31/173). 17/314). 14/25 |
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Answer» GIVEN, cosec2 θ = 625/576 ⇒ SIN2 θ = 1/cosec2 θ = 576/625 ⇒ sin θ = √(576/625) = 24/25 As we know, COS2 θ = 1 – sin2 θ = 1 – 576/625 = 49/625 ⇒ cos θ = √(49/625) = 7/25 ∴ [(sin θ – cos θ)/(sin θ + cos θ)] = (24/25 – 7/25)/(24/25 + 7/25) = (17/25)/(31/25) = 17/31 |
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