1.

If cosec2 θ = 625/576, then what is the value of [(sin θ – cos θ)/(sin θ + cos θ)]?1). 12). 31/173). 17/314). 14/25

Answer»

GIVEN, cosec2 θ = 625/576

SIN2 θ = 1/cosec2 θ = 576/625

⇒ sin θ = √(576/625) = 24/25

As we know, COS2 θ = 1 – sin2 θ = 1 – 576/625 = 49/625

⇒ cos θ = √(49/625) = 7/25

∴ [(sin θ – cos θ)/(sin θ + cos θ)] = (24/25 – 7/25)/(24/25 + 7/25) = (17/25)/(31/25) = 17/31


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