If equations of a projectile projected at angle θ with horizontal are

1.	If equations of a projectile projected at angle θ with horizontal are followingx = 15t (m)y = 15t – 5t2 (m), (where x and y are co-ordinates) then the initial velocity is given by
Answer» ANSWER: EQUATION of trajectory is Y=Xtanθ−2u2gX2(1+tan2θ) On Comparison with GIVEN equation xtanθ=4t ⇒(3t)tanθ=4t ⇒tanθ=34 θ=tan−1(4/3)≈530

If equations of a projectile projected at angle θ with horizontal are followingx = 15t (m)y = 15t – 5t2 (m), (where x and y are co-ordinates) then the initial velocity is given by

Answer»

ANSWER:

EQUATION of trajectory is Y=Xtanθ−2u2gX2(1+tan2θ)

On Comparison with GIVEN equation

xtanθ=4t

⇒(3t)tanθ=4t

⇒tanθ=34

θ=tan−1(4/3)≈530

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If equations of a projectile projected at angle θ with horizontal are followingx = 15t (m)y = 15t – 5t2 (m), (where x and y are co-ordinates) then the initial velocity is given by

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