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If `f(y) = (y)/(sqrt(1-y^(2))), g(y) = (y)/(sqrt(1+y^(2)))`, then (fog) y is equal toA. `(y)/(sqrt(1-y^(2)))`B. `(y)/(sqrt(1+y^(2)))`C. yD. `((1-y^(2)))/(sqrt(1-y^(2)))` |
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Answer» Correct Answer - C `f(y)=(y)/(sqrt((1-y^(2)))),g(y)=(y)/(sqrt((1+y^(2))))` and `(fog)y=f(g(y))=f((y)/(sqrt((1+y^(2)))))=((y)/(sqrt((1+y^(2)))))/(sqrt(1-(y^(2))/((1+y^(2)))))=((y)/(sqrt((1+y^(2)))))/((1)/(sqrt((1+y^(2)))))=y` |
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