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If `f(z)=(7-z)/(1-z^2)`, where `z=1+2i ,`then `|f(z)|`is`(|z|)/2`(b) `|z|`(c) `2|z|`(d) none of theseA. `(|z|)/(2)`B. `|z|`C. `2|z|` None of theseD. |
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Answer» Correct Answer - A Let z = 1 + 2i `rArr |z|= sqrt( 1+ 4 ) = sqrt(5)` Now. `f(z) = (7-z)/(1-z^(2))=(7-1-2i)/(1-(1+2i)^(2))` `(6-2i)/(1-1-4i^(2)-4i)=(6-2i)/(4-4i)` `((3-i)(2+2i))/((2-2i)(2+2i))` `(6-2i+6i-2i^(2))/(4-4i^(2))=(6+4i+2)/(4+4)` `(8+4i)/(8)=1+(1)/(2)i` `f(z) = 1 + (1)/(2)i` ` :. |f(z)|=sqrt( 1+(1)/(4))=sqrt((4+1)/4)=sqrt(5)/(2) = (|z|)/(2)` |
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