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If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times the least, then the numbers are :A. 5, 10, 15, 20 B. 4, 10, 16, 22 C. 3, 7, 11, 15 D. none of these |
Answer» Option : (A) Let 4 numbers of A.P. be the a, a+d, a+2d, a+3d. Here, Given that their sum is 50. i.e., a+a+d+a+2d+a+3d = 50 ∴ 4a + 6d = 50 ∴ 2a + 3d = 25 ....(1) Also, Given that, The greatest number is 4 times the least. i.e., 4a = a + 3d ∴ 3a = 3d ∴ a = d Substituting a=d in (1) we get, 5a = 25 ∴ a = 5 And, d = a = 5 So, numbers are a = 5; a+d = 5+5; a+2d = 5+2(5); a+3d = 5+3(5) i.e. 5,10,15,20 |
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