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If \(\frac{3}{5}\) of a number exceeds its \(\frac{2}{7}\) by \(44\) , find the number. |
Answer» Let the number be x \(\frac{3}{5}\) of x \(=\frac{3}{5}\text{x}\) \(\frac{2}{7}\) of x \(=\frac{2}{7}\text{x}\) According to the question, \(\frac{3}{5}\text{x}-\frac{2}{7}\text{x}=44\) \(\Rightarrow\) \(\frac{3\text{x}\times7-2\text{x}\times5}{35}=44\) \(\Rightarrow\) \(\frac{21\text{x}-10\text{x}}{35}=44\) \(\Rightarrow\) \(\frac{11}{35}\times\text{x}=44\) \(\Rightarrow\) \(\text{x}=44\div\frac{11}{35}\) \(\Rightarrow\) \(\text{x}=44\times\frac{35}{11}\) \(\Rightarrow\) \(\text{x}=\frac{1540}{11}\) \(\Rightarrow\) \(\text{x}=140\) The number is 140 |
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