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    				| 1. | If \(\frac{6x\,+\,1}{3}+1=\frac{x-3}{6}\) then x = ?A. 1 B. - 1 C. 3 D. - 3 | 
| Answer» \(\frac{6x\,+\,1}{3}+1\) = \(\frac{x\,-\,3}{6}\) Taking LCM of 1 and 3 = 3, \(\frac{6\text{x}\,+\,1\,+\,3}{3}=\frac{\text{x}-3}{6}\) ⇒ 2(6x + 4) = (x - 3) ⇒ 12x - x = - 3 - 8 ⇒ x = - 1 | |