1.

Write 'T' for true and 'F' for false for each of the following:(i) (5 - 3x2) is a binomial. (ii) - 8 is a monomial. (iii) (5a - 9b) - ( - 6a + 2b) = ( - a - 7b).(iv) When x = 2 and y = 1, the value of \(\frac{-8}{7}x^3y^3\) is \(\frac{-64}{7}\)(v) \(\frac{x}{4}+\frac{x}{6}-\frac{x}{2}=\frac{3}{4}\) \(\Rightarrow x=-9\)(vi) 2x - 5 = 0 \(\Rightarrow x=\frac{2}{5}\)

Answer»

(i) True 

It has two terms so binomial. 

(ii) True 

It has single term so monomial. 

(iii) False 

(5a - 9b) - ( - 6a + 2b) = 5a + 6a - 9b - 2b = 11a - 11b 

(iv) True

\(\frac{-8}{7}x^3y^4=\frac{-8}{7}\times8\times1=\frac{-64}{7}\)

(v) True 

Taking the LCM of 4,6 and 2 = 12

\(\frac{3\text{x}\,+\,2\text{x}-\,6\text{x}}{12}=\frac{3}{4}\)

\(\Rightarrow\) -4x = 36

\(\Rightarrow\) x = -9

(vi) False

2x - 5 = 0

\(\Rightarrow \text{x}=\frac{5}{2}\)



Discussion

No Comment Found