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    				| 1. | Write 'T' for true and 'F' for false for each of the following:(i) (5 - 3x2) is a binomial. (ii) - 8 is a monomial. (iii) (5a - 9b) - ( - 6a + 2b) = ( - a - 7b).(iv) When x = 2 and y = 1, the value of \(\frac{-8}{7}x^3y^3\) is \(\frac{-64}{7}\)(v) \(\frac{x}{4}+\frac{x}{6}-\frac{x}{2}=\frac{3}{4}\) \(\Rightarrow x=-9\)(vi) 2x - 5 = 0 \(\Rightarrow x=\frac{2}{5}\) | 
| Answer» (i) True It has two terms so binomial. (ii) True It has single term so monomial. (iii) False (5a - 9b) - ( - 6a + 2b) = 5a + 6a - 9b - 2b = 11a - 11b (iv) True \(\frac{-8}{7}x^3y^4=\frac{-8}{7}\times8\times1=\frac{-64}{7}\) (v) True Taking the LCM of 4,6 and 2 = 12 \(\frac{3\text{x}\,+\,2\text{x}-\,6\text{x}}{12}=\frac{3}{4}\) \(\Rightarrow\) -4x = 36 \(\Rightarrow\) x = -9 (vi) False 2x - 5 = 0 \(\Rightarrow \text{x}=\frac{5}{2}\) | |