1.

Solve:\(\frac{3(y\,-\,5)}{4}-4y=3-\frac{(y\,-\,3)}{2}\)3(y - 5)/4 - 4y = 3 - (y - 3)/2

Answer»

\(\frac{3(y\,-\,5)}{4}-4y=3-\frac{(y\,-\,3)}{2}\)

Taking LCM of 4 and 1 on LHS = 4 and 1 and 2 on RHS = 2

\(\frac{3(y\,-\,5)-16y}{4}=\frac{6\,-\,y\,+\,3}{2}\)

By cross multiplication 

⇒ 3y - 15 - 16y = 2(9 - y) 

⇒ - 13y + 2y = 18 + 15 

⇒ - 11y = 33 

⇒ y = - 3



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