1.

If \(\frac{x\,+\,1}{2x\,+\,3}=\frac{3}{8},\) then x = ?A. \(\frac{1}{4}\)B. \(\frac{1}{3}\)C. \(\frac{1}{6}\)D. \(\frac{1}{2}\)

Answer»

\(\frac{x\,+\,1}{2x\,+\,3}=\frac{3}{8}\)

By cross multiplication, 8(x + 1) = 3(2x + 3)

⇒ 8x - 6x = 9 - 8 

⇒ 2x = 1

⇒ \(\text{x}=\frac{1}{2}\)



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