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    				| 1. | If \(\frac{x\,+\,1}{2x\,+\,3}=\frac{3}{8},\) then x = ?A. \(\frac{1}{4}\)B. \(\frac{1}{3}\)C. \(\frac{1}{6}\)D. \(\frac{1}{2}\) | 
| Answer» \(\frac{x\,+\,1}{2x\,+\,3}=\frac{3}{8}\) By cross multiplication, 8(x + 1) = 3(2x + 3) ⇒ 8x - 6x = 9 - 8 ⇒ 2x = 1 ⇒ \(\text{x}=\frac{1}{2}\) | |