InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
If he expression `[m x-1+(1//x)]`is non-negative for all positive real `x ,`then the minimum value of `m`must be`-1//2`b. `0`c. `1//4`d. `1//2`A. `-1//2`B. 0C. `1//4`D. `1//2` |
|
Answer» Correct Answer - 3 We know that `ax^(2) + bx c ge 0, AA x in R`, if `a gt 0 and b^(2) - 4ac le 0.` So, `mx - 1 + 1/x ge 0` or `(mx^(2) - x + 1)/(x) ge 0` or `mx^(2) - x + 1 ge 0` as `x gt 0`. Now, `mx^(2) - x + 1 ge 0` if `m gt 0` and `1 - 4m le 0` `rArr m gt 0 and m ge 1//4` Thus, the minimum value of m is 1/4. |
|