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.If ifference of two unit vectors is a unit vector, prove that magnitude of their sum is `sqrt3` |
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Answer» `| vec a| = 1, | vec b|=1` `| vec a - vec b | = 1` `sqrt( a^2 + b^2 - 2 vec a vec b cos theta) = 1` `sqrt(1 + 1 - 2*1*1*cos theta) = 1` `1 + 1 - 2 cos theta = 1` `2cos theta = 1` `cos theta = 1/2` `|vec a + vec b| = | vec a|^2 + |vec b|^2 + 2|vec a|| vec b| cos theta` `= sqrt( 1 + 1 + 2 xx1/2)` `= sqrt3` Hence proved |
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