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If initial concentration is doubled, the time for half-reaction is also doubled, the order of reaction isA. zeroB. firstC. secondD. third |
Answer» Correct Answer - A For nth order reaction, `t_(1//2)propa^(1-n)` Here, `t_(1//2)propa` Hence, 1 - n or n = 0 (i.e. zero order reaction) |
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