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If iron atom is available in the form of , say three isotopes ""_(25)^(54)"Fe", ""_(26)^(56)Fe and " "_(26)^(57)Fe and their proportion is 5% , 90% and 5% respectively. Calculate the average mass of iron atom. |
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Answer» SOLUTION :The AVERAGE atomlc mass of IRON `= (am + bn + cz)/((m + N + z))` = `(54 xx 5 + 56 xx 90 + 57 xx 5)/(5 + 90 + 5 ) ` `= (270 + 5040 + 285 )/(100)` = `(5595)/(100)` = ` 55.95` u |
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