If k, (2k – 1) and (2k + 1) are the three successive terms of an AP,

1.	If k, (2k – 1) and (2k + 1) are the three successive terms of an AP, find the value of k.
Answer» Given: k, (2k – 1) and (2k + 1) are the three successive terms of an AP. So, (2k – 1) – k = (2k + 1) – (2k – 1) 2 (2k – 1) = 2k + 1 + k 4k – 2 = 3k + 1 4k – 3k = 1 + 2 or k = 3 The value of k is 3.

If k, (2k – 1) and (2k + 1) are the three successive terms of an AP, find the value of k.

Answer»

Given: k, (2k – 1) and (2k + 1) are the three successive terms of an AP.

So, (2k – 1) – k = (2k + 1) – (2k – 1)

2 (2k – 1) = 2k + 1 + k

4k – 2 = 3k + 1

4k – 3k = 1 + 2

or k = 3

The value of k is 3.