If `K_(h)` (hydrolysis constant) for anilinium ion is `2.4xx10^(-5) M`, then `K_(b)` for aniline will beA. `4.1xx10^(10)`B. `4.1xx10^(-10)`C. `2.4xx10^(9)`D. `2.4xx10^(-19)`

If `K_(h)` (hydrolysis constant) for anilinium ion is `2.4xx10^(-5) M`

1.	If `K_(h)` (hydrolysis constant) for anilinium ion is `2.4xx10^(-5) M`, then `K_(b)` for aniline will beA. `4.1xx10^(10)`B. `4.1xx10^(-10)`C. `2.4xx10^(9)`D. `2.4xx10^(-19)`
Answer» Correct Answer - B `K_(h)` for anilinium ion `=2.4xx10^(-5) M` `K_(h)=(K_(w))/(K_(b))` `K_(b)=(10^(-14))/(2.4xx10^(-5))=4.1xx10^(-10)`

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If `K_(h)` (hydrolysis constant) for anilinium ion is `2.4xx10^(-5) M`, then `K_(b)` for aniline will beA. `4.1xx10^(10)`B. `4.1xx10^(-10)`C. `2.4xx10^(9)`D. `2.4xx10^(-19)`

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