If `K_(sp)` for `HgSO_(4)` is `6.4xx10^(-5)`, then solubility of this substance in mole per `m^(3)` isA. `8xx10^(-3)`B. `6.4xx10^(-5)`C. `8xx10^(-6)`D. None of these

If `K_(sp)` for `HgSO_(4)` is `6.4xx10^(-5)`, then solubility of this

1.	If `K_(sp)` for `HgSO_(4)` is `6.4xx10^(-5)`, then solubility of this substance in mole per `m^(3)` isA. `8xx10^(-3)`B. `6.4xx10^(-5)`C. `8xx10^(-6)`D. None of these
Answer» Correct Answer - A `K_(sp)=s^(2)` `s=sqrt(K_(sp))=sqrt(6.4xx10^(-5))` `s=8xx10^(-3)` `s=8mol//m^(3)`

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If `K_(sp)` for `HgSO_(4)` is `6.4xx10^(-5)`, then solubility of this substance in mole per `m^(3)` isA. `8xx10^(-3)`B. `6.4xx10^(-5)`C. `8xx10^(-6)`D. None of these

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