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If `lambda_(1), lambda_(2), lambda_(3)` are the wavelengths of the waves giving resonance in the fundamental, first and second overtone modes respecively in a open organ pipe, then the ratio of the wavelengths `lambda_(1) : lambda_(2) : lambda_(3)`, is :A. `1 : 2 : 3`B. `1 : 3 : 5`C. `1 : 1//2 : 1//3`D. `1 : 1//3 : 1//5` |
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Answer» Correct Answer - C `n_(1) : n_(2) : n_(3) = 1 : 2 : 3` `(V)/(lambda_(1)) : (V)/(lambda_(2)) : (V)/(lambda_(3)) = 1 : 2 : 3` `lambda_(1) : lambda_(2) : lambda_(3) = 1 : (1)/(2) : (1)/(3)` |
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