If length of major axis is 10 and minor axis is 8 and major axis is along x-axis then find the equation of ellipse.(a) \((\frac{x}{4})^2+(\frac{y}{5})^2\)=1(b) \((\frac{x}{5})^2+(\frac{y}{4})^2\)=1(c) \((\frac{x}{10})^2+(\frac{y}{8})^2\)=1(d) \((\frac{x}{8})^2+(\frac{y}{10})^2\)=1The question was posed to me in an interview for job.This interesting question is from Conic Sections topic in portion Conic Sections of Mathematics – Class 11

If length of major axis is 10 and minor axis is 8 and major axis is al

1.	If length of major axis is 10 and minor axis is 8 and major axis is along x-axis then find the equation of ellipse.(a) \((\frac{x}{4})^2+(\frac{y}{5})^2\)=1(b) \((\frac{x}{5})^2+(\frac{y}{4})^2\)=1(c) \((\frac{x}{10})^2+(\frac{y}{8})^2\)=1(d) \((\frac{x}{8})^2+(\frac{y}{10})^2\)=1The question was posed to me in an interview for job.This interesting question is from Conic Sections topic in portion Conic Sections of Mathematics – Class 11
Answer» The CORRECT CHOICE is (B) \((\frac{X}{5})^2+(\frac{y}{4})^2\)=1 Easy explanation: GIVEN, 2a=10 => a=5 and 2b=8 => b=4. Equation of ellipse with major axis along x-axis is \((\frac{x}{a})^2+(\frac{y}{b})^2\)=1. So, equation of given ellipse is \((\frac{x}{5})^2+(\frac{y}{4})^2\)=1.

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