1.

If M=2- _/3 Find The Value Of: M^6+m^5+m^4+1)/m^3?

Answer»

m = (2 - ?3)

=> 1/m = (2 + ?3)

(m^6+m^5+m^4+1)/m^3

= m^3 + m^2 + m + 1/m^3

= (m + 1/m)^3 - 3(m +1/m) + m(m+1)

= 4^3 - 3*4 + (2-?3)(3-?3)

= 64 - 12 + 9 - 5?3

= (61 - 5?3).

m = (2 - ?3)

=> 1/m = (2 + ?3)

(m^6+m^5+m^4+1)/m^3

= m^3 + m^2 + m + 1/m^3

= (m + 1/m)^3 - 3(m +1/m) + m(m+1)

= 4^3 - 3*4 + (2-?3)(3-?3)

= 64 - 12 + 9 - 5?3

= (61 - 5?3).


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