if m, p and L denote mass,linear momentum and angular momentum of a pa

1.	if m, p and L denote mass,linear momentum and angular momentum of a particle moving in circle of radius r,then its rotational K.E cen be expressed as:
Answer» The Expression for Rotational Kinetic ENERGY is: Kinetic energy is given by the expression $K.E = M * v^{2}/2$ where M is the mass and v is the VELOCITY of moving body. linear momentum is given as $p = M * v$ therefore by MULTIPLYING and DIVIDING by M, the kinetic energy expression becomes $K.E = p^{2} /(2 * M)$ Angular moment is given by $L = M * v * R$ $L = p * R\\p = L/R$ where R is the radius with which the particle moves. now substituting the above equation in the K.E expression ,we GET the rotational Kinetic energy expression: Ans: $K.E = L^{2} /(2R^{2} M)$