1.

If n equal rain droplets falling through air with equal steady velocity of `10 cm s^(-1)` coalesce, find the terminal velocity of big drop formed.

Answer» Let, R be the radius of each droplet and big drop respectively. Volume of big drop = n x volume of a small droplet
`(4)/(3) pi R^(3) =nxx(4)/(3)pi r^(3)`
or `R=n^(1//3)r`
Terminal velocity of small droplet,
`v=(2r^(2)(rho-sigma)g)/(9eta)`
Terminal velocity of big drop,
`V=(2R^(2)(rho-sigma)g)/(9eta)`
Dividing (ii) by (i), we get
`(V)/(v)=(R^(2))/(r^(2))=(n^(1//3)r^(2))/(r^2)=n^(2//3)` or `V=n^(2//3) v cm//s`


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