1.

If n is an integer and if sin`theta` = 1, prove that `theta` = (4n+1)`pi/2`

Answer» `Sin theta = 1 => sin theta = sin (pi/2)`
`theta = (pi/2)`
Also, we know, `sin theta = sin (2npi+theta)`
Here, `n` is an integer.
`:. theta = (2npi+(pi/2))`
`=> theta = (4npi+pi)/2=>(pi/2)(4n+1)`
`:. theta = (4n+1)(pi/2)`


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