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If n is an integer and if sin`theta` = 1, prove that `theta` = (4n+1)`pi/2` |
Answer» `Sin theta = 1 => sin theta = sin (pi/2)` `theta = (pi/2)` Also, we know, `sin theta = sin (2npi+theta)` Here, `n` is an integer. `:. theta = (2npi+(pi/2))` `=> theta = (4npi+pi)/2=>(pi/2)(4n+1)` `:. theta = (4n+1)(pi/2)` |
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