1.

If N Is An Integer, When (2n + 2)^2 Is Divided By 4 The Remainder Is?

Answer»

We first expand (2n + 2)2 

(2n + 2)^2 = 4n^2 + 8N + 4 

FACTOR 4 out. 

= 4(n^2 + 2n + 1) 

(2n + 2)2 is divisible by 4 and the remainder is equal to 0. 

We first expand (2n + 2)2 

(2n + 2)^2 = 4n^2 + 8n + 4 

Factor 4 out. 

= 4(n^2 + 2n + 1) 

(2n + 2)2 is divisible by 4 and the remainder is equal to 0. 


Discussion

No Comment Found

Related InterviewSolutions