If N (k1, 0.5) = (19.5, k2), then find the values of k1 and k2.

1.	If N (k1, 0.5) = (19.5, k2), then find the values of k1 and k2.
Answer» N (k₁, 0.5) = (19.5, k₂) k₁ – <5 = 19.5, k₁ + S = k₂ Here, δ = 0.5 ∴ k₁ – 0.5 = 19.5 ∴ k₁ = 19.5 + 0.5 = 20 Putting k₁ – 20 and δ = 0.5 in k₁ + δ = k₂, 20 + 0.5 = k₂ k₂ = 20.5 Hence, k₁ = 20, k₂ = 20.5

Answer»

N (k₁, 0.5) = (19.5, k₂)

k₁ – <5 = 19.5, k₁ + S = k₂

Here, δ = 0.5

∴ k₁ – 0.5 = 19.5

∴ k₁ = 19.5 + 0.5 = 20

Putting k₁ – 20 and δ = 0.5 in k₁ + δ = k₂,

20 + 0.5 = k₂

k₂ = 20.5

Hence, k₁ = 20, k₂ = 20.5

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